How much energy will a 300 W electric iron consume in 2 hours of operation?

To determine the cost of electricity used by an electric iron, we apply the formula: W = P * t.

Values of variables: P – power of the used iron (P = 300 W); t is the duration of the iron (t = 2 h = 7200 s).

Calculation: W = P * t = 300 * 7200 = 2.16 * 106 J = 2.16 MJ or 0.6 kW * h.

Answer: For 2 hours of operation, the used iron consumes 2.16 MJ (0.6 kWh) of electricity.



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