How much energy will a piece of lead weighing 500 g acquire when heated when the temperature changes by 200 ° C.

univerkov | July 10, 2021 | education

Problem data: m (mass of a piece of lead) = 500 g (0.5 kg); Δt (change in temperature of the taken piece of lead) = 200 ºС.

Reference values: С (specific heat capacity of lead) = 140 J / (kg * ºС).

The energy that a piece of lead will acquire when heated is determined by the formula: Q = C * m * Δt.

Calculation: Q = 140 * 0.5 * 200 = 14 * 10 ^ 3 J (14 kJ).

Answer: When heated at 200 ºС, the taken piece of lead will acquire 14 kJ of thermal energy.

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