How much energy will be released during the condensation of 200 g of alcohol taken at a temperature of 78 ° C?

Initial data: m (weight of alcohol taken) = 200 g; t (initial temperature of alcohol, boiling point of ethyl alcohol) = 78 ºС.

Reference values: L (specific heat of vaporization) = 0.9 * 10 ^ 6 J / kg.

SI system: m = 200 g = 200/1000 kg = 0.2 kg.

The amount of energy released during the condensation of a given mass of alcohol is determined from the following formula: Q = L * m.

Let’s do the calculation:

Q = 0.9 * 10 ^ 6 * 0.2 = 0.18 * 10 ^ 6 J.

Answer: When condensing 200 grams of alcohol, 0.18 * 10 ^ 6 J of energy will be released.