How much energy will be released during the decay of m = 15 g of uranium 235/92 U, if the fission of one nucleus releases the energy W1 = 200 MeV
Let’s find the amount of matter and the number of uranium-235 atoms:
n (U) = m (U) / M (U) = 15/235 = 0.0638;
N (U) = n (U) * NA = 0.0638 * 6.02 * 1023 = 3.843 * 10 ^ 22;
Let’s find the amount of released energy:
E = W1 * N (U) = 2 * 10 ^ 11 * 3.843 * 10 ^ 22 = 7.685 * 1033 eV.
Answer: E = 7.685 * 1033 eV.
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