How much energy will be released in the form of heat when boiling water with a mass of 10 kg cools down to 20 degrees Celsius.

To find the thermal energy released during cooling of boiling water, we apply the formula: Q = Cw * m * (tboil – tk).
Values of variables and constants: Sv – specific heat capacity of water (Sv = 4200 J / (kg * K)); m is the mass of boiling water (m = 10 kg); tboil – boiling water temperature (tboil = 100 ºС); tк – final temperature (tк = 20 ºС).
Calculation: Q = Cw * m * (tboil – tc) = 4200 * 10 * (100 – 20) = 3.36 * 10 ^ 6 J (3.36 MJ).
Answer: 3.36 MJ of thermal energy should be released in the form of heat.