How much ethane can be obtained by reacting 49.2 g of sodium acetate with solid sodium hydroxide?

How much ethane can be obtained by reacting 49.2 g of sodium acetate with solid sodium hydroxide? The product yield is 75% of the theoretically possible.

1. Let’s write the equation:
CH3COONa + NaOH = CH4 + Na2CO3 – exchange reaction, methane was obtained;
2. Let’s calculate the molar masses of substances:
M (CH3COONa) = 81.9 g / mol;
M (CH4) = 16 g / mol.
3. Determine the number of moles of sodium acetate, if its mass is known:
Y (CH3COONa) = m / M = 49.2 / 81.9 = 0.6 mol;
According to the reaction equation, the amount of moles of sodium acetate and methane salt is 1 mole, which means that Y (ICH4) = 0.6 mole.
4. Let’s calculate the theoretical volume of methane:
V (CH4) = 0.6 * 22.4 = 9.6 liters.
V (CH4) practical = 0.75 * 9.6 = 7.2 liters.
Answer: the volume of methane is 7.2 liters.



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