How much ethanol is produced during glucose fermentation if 11.2 m3 of CO2 is released

univerkov | February 1, 2021 | education

C6H12O6 = 2C2H5OH + 2CO2.
In order to find the amount of a gas substance, you need to divide the volume of this gas by the molar volume – a constant equal to about 22.4 l / mol.
υ = V / Vm = 11.2 m ^ 3 / 22.4 l / mol = 11200 l / 22.4 l / mol = 500 mol.
m = n * M = 500 mol * 46 g / mol = 23000 g = 23 kg.
Answer: m = 23 kg.

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