How much ether, taken at a temperature of 35 degrees Celsius, boiled away if 6 kJ of heat was reported to it?

Task data: t0 (ether temperature before heat transfer) = 35 ºС (corresponds to the vaporization temperature); Q (heat reported to the ether) = 6 kJ or 6 * 10 ^ 3 J.

Constants: L (specific heat of vaporization of ether) = 0.4 * 10 ^ 6 J / kg.

We express the mass of the boiled away ether from the formula: Q = L * m, whence m = Q / L.

Let’s calculate: m = 6 * 10 ^ 3 / (0.4 * 10 ^ 6) = 15 * 10 ^ -3 kg (15 g).

Answer: After transferring 6 kJ of heat, 15 grams of ether will boil away.