How much ethylene needs to be oxidized to obtain 310 g of ethylene glycol.

Given:
m (C2H4 (OH) 2) = 310 g

To find:
V (C2H4) -?

1) Write the reaction equation:
3C2H4 + 2KMnO4 + 4H2O => 3C2H4 (OH) 2 + 2MnO2 + 2KOH;
2) Calculate the molar mass of ethylene glycol:
M (C2H4 (OH) 2) = 62 g / mol;
3) Calculate the amount of ethylene glycol substance:
n (C2H4 (OH) 2) = m / M = 310/62 = 5 mol;
4) Determine the amount of ethylene substance (taking into account the coefficients in the reaction equation):
n (C2H4) = n (C2H4 (OH) 2) = 5 mol;
5) Calculate the volume of ethylene (under normal conditions):
V (C2H4) = n * Vm = 5 * 22.4 = 112 liters.

Answer: The volume of C2H4 is 112 liters.