How much ethylene should be taken to obtain 108 g of butadiene. Draw up a scheme for polymerization of butadiene.

The solution of the problem:
1. Let’s compose the reaction equations:
Н2С = СН2 + Н2О = С2Н5ОН – ethylene hydration, ethanol obtained;
2C2H5OH = H2C – CH – CH = CH2 + 2H2O + H2 – Lebedev reaction, butadiene was formed;
2. Let’s make calculations: M (C4H6) = 54 g / mol; Y (C4H6) = m (C4H6) / M (C4H6);
Y (C4H6) = 108/54 = 2 mol;
3. Let’s compose the proportion according to the data of the reaction equation:
X mol (C2H4) – 2 mol (C4H6);
-1 mol -1 mol hence, X mol (C2H4) = 2 mol;
4. Let’s calculate the volume of ethylene, applying Avogadro’s law:
V (C2H4) = 2 * 22.4 = 44.8 liters.
Answer: 44.8 liters are needed to obtain butadiene.
Butadiene is used to obtain rubber, we write down the reaction equation for its synthesis:
n H2C – CH – CH = CH2 = (- H2C – CH – CH – CH2 -) n – polymerization reaction, synthetic butadiene rubber was obtained.