How much force does it take to move a 70 kg cabinet? Friction coefficient = 0.3

Initial data: m (weight of the cabinet to be moved) = 70 kg; μ (coefficient of sliding friction) = 0.3.

Reference data: g (acceleration due to gravity) = 10 m / s2.

To move the cabinet from its place, it is necessary to overcome the sliding friction force, which can be calculated by the formula: Ftr. = μ * m * g.

Let’s make a calculation: Ftr. = 0.3 * 70 * 10 = 210 N.

Answer: To move the cabinet from its place, you will need to apply a force of 210 N.