How much force must be applied to the lever to lift a stone weighing 9 kg.
| December 11, 2020 | education
Take the fulcrum in the middle of the lever, then: The arms of the lever are the same L1 = L2 Moment of forces: М1 = М2 F1L1 = F2L2 F1L1 = F2L1 L1 shortens F1 = F2 F2 = mg => F1 = mg F1 = 9kg * 10 N / kg = 90 N
Answer: 90 N must be applied to lift a 9 kg load.
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