How much gas is produced by the interaction of 50 grams of Ca carbonate with HCL?

The reaction of dissolving chalk in hydrochloric acid is described by the following chemical reaction equation:

CaCO3 + 2HCl = CaCl2 + CO2 + H2O;

When 1 mol of chalk is dissolved in acid, 1 mol of gaseous carbon dioxide is synthesized. This consumes 2 mol of hydrochloric acid.

Let’s calculate the available chemical amount of calcium carbonate substance.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 50/100 = 0.5 mol;

Thus, when 0.5 mol of limestone is dissolved, 0.5 mol of carbon dioxide is synthesized.

Let’s calculate its volume. To do this, multiply the amount of the substance and the standard volume of 1 mole of the gaseous substance. 1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V CO2 = 0.5 x 22.4 = 11.2 liters;