How much gas will be released when exposed to potassium carbonate 250g. 14% nitric acid solution.

| February 27, 2021 | education

Given:

m (solution) = 250 g,

W = 14%.

V (CO2) -?

Find the mass of nitric acid in the solution.

W = m (substance): m (solution) × 100%,

hence m (substance) = (m (solution) × w): 100%.

m (substance) = (250 g × 14%): 100% = 35 g.

Let’s find the amount of nitric acid substance by the formula:

n = m: M.

M (HNO3) = 1+ 14 + 48 = 63 g / mol.

n = 35 g: 63 g / mol = 0.56 mol.

Let’s compose the reaction equation, find the quantitative ratios of substances.

CaCO3 + 2HNO3 = Ca (NO3) 2 + CO2 + H2O.

According to the reaction equation, 2 mol of nitric acid accounts for 1 mol of carbon dioxide. The substances are in quantitative ratios of 2: 1.

The amount of carbon dioxide substance will be 2 times less than the amount of nitric acid substance.

n (CO2) = 0.56: 2 = 0.28 mol.

V = Vn n, where Vn is the molar volume of gas, equal to 22.4 l / mol, and n is the amount of substance.

V = 0.28 mol × 22.4 L / mol = 6.272 L.

Answer: 6.272 liters.



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