How much gasoline do you need to burn to melt 200 g of tin at 32 degrees?

Initial data: m1 (tin mass) = 200 g = 0.2 kg; t (initial temperature) = 32 ºС; no heat loss.

Constants: tmelt (melting point) = 232 ºС; C (specific heat of tin) = 230 J / (kg * K); λ (specific heat of fusion of tin) = 0.59 * 10 ^ 5 J / kg; q (specific heat of combustion of gasoline) = 4.6 * 10 ^ 7 J / kg.

Q1 + Q2 = Q3: С * m1 * (tmelt – t) + λ * m1 = q * m2.

m2 = (C * m1 * (tmelt – t) + λ * m1) / q = (230 * 0.2 * (232 – 32) + 0.59 * 10 ^ 5 * 0.2) / (4.6 * 10 ^ 7) ≈ 4.6 * 10 ^ -4 kg = 0.46 g.