How much gasoline is consumed in an internal combustion engine that drives a pump that draws 4 tons of oil from a depth of 1,500 meters? Motor efficiency 30%
η = (A / Q) * 100%, η = 30% = 0.3, A is useful work (A = Ft * h, Ft = m * g (m is the mass of oil (m = 4 t = 4000 kg) , g is the acceleration of gravity (g = 10 m / s2)), h is the height of oil rise (h = 1500 m)), Q is the energy expended due to the combustion of gasoline (Q = q * m1, q is the specific heat of combustion of gasoline (q = 44 MJ = 44 * 10 ^ 6 J / kg), m1 is the mass of consumed gasoline).
η = m * g * h / (q * m1).
m1 = m * g * h / (q * η) = 4000 * 10 * 1500 / (44 * 10 ^ 6 * 0.3) = 4.55 kg.
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