How much gasoline will an internal combustion engine use when pulling 4 tons of oil from a depth of 1500 m?
| December 13, 2020 | education
How much gasoline will an internal combustion engine use when pulling 4 tons of oil from a depth of 1500 m? Motor efficiency 30% q = 44 kJ / kg
n-efficiency, Ap- useful work, Az-expended.
n = Ap / Az
Ap = F * ΔS
Az = Q combustion = qm
Substituting, we get:
m gasoline = mgΔs / nq = 4000 * 10 * 1500 / 0.3 * 44000 = 4545 kg
If volume is needed, then V = m / p (density) = 4545/750 = 6 cubic meters
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