How much glucose was alcohol fermented to produce 8.96 liters of carbon dioxide?

univerkov | December 8, 2020 | education

Let’s compose the reaction equation:
С6H12O6 = 2C2H5OH + 2CO2.
We consider the molar mass of glucose:
12 * 6 + 1 * 12 + 16 * 6 = 72 + 12 + 96 = 180 (g / mol).
Using Avogadro’s number – 22.4 L / mol, we calculate the volume of carbon dioxide released as a result of the reaction in the equation:
2 * 22.4 = 44.8 (l).
We make up the proportions and calculate the mass of glucose:
8.96 * 180 / 44.8 = 36 (g).
Answer: 36 g of glucose is needed to release 8.96 liters of CO2.

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.