How much gunpowder burned out if 28 kJ of heat was released.

univerkov | March 24, 2021 | education

Combustion of gunpowder (Q (released amount of heat) = 28 kJ = 28 * 10 ^ 3 J; q (specific heat of combustion of gunpowder) = 3.8 * 10 ^ 6 J / kg): Q = q * m and m = Q / q = 28 * 10 ^ 3 / (3.8 * 10 ^ 6) = 7.37 * 10 ^ -3 kg = 7.37 g.

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