How much H will be released if zinc with a mass of 13 g has reacted with sulfuric acid?

univerkov | May 17, 2021 | education

1. Let’s write down the reaction equation:

Zn + H2SO4 = ZnSO4 + H2.

2. Find the amount of zinc:

n (Zn) = m (Zn) / M (Zn) = 13 g / 65 g / mol = 0.2 mol.

3. According to the reaction equation, we find the amount, and then the volume of hydrogen (Vm is the molar volume, a constant equal to 22.4 l / mol)

n (H2) = n (Zn) = 0.2 mol.

V (H2) = n (H2) * Vm = 0.2 mol * 22.4 L / mol = 4.48 L.

Answer: V (H2) = 4.48 liters.

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