How much H2 will be released when 13 g of zinc reacts with HCl?

Let’s implement the solution:

In accordance with the condition of the problem, we will write the data:
Zn + 2HCl = ZnCl2 + H2 – OBP, hydrogen is evolved;

Let’s make the calculations:
M (Zn) = 65.3 g / mol;

M (H2) = 2 g / mol.

Determine the amount of the original substance:
Y (Zn) = m / M = 13 / 65.3 = 0.2 mol;

Y (H2) = 0.2 mol since the amount of substances is 1 mol.

We find the volume of H2:
V (H2) = 0.2 * 22.4 = 4.48 L

Answer: hydrogen produced with a volume of 4.48 liters