How much H2SO4 reacted with NaOH, if as a result 36 g of H2O was released.

Let’s execute the solution:
1. According to the condition of the problem, we compose the equation:
H2SO4 + 2NaOH = Na2SO4 + 2H2O – ion exchange, sodium sulfate, water is released;
2. We make calculations by the formulas:
M (H2SO4) = 98 g / mol.
M (H2O) = 18 g / mol.
3. Determine the amount of the product:
Y (H2O) = m / M = 36/18 = 2 mol.
Y (H2SO4) = 2 mol since the amount of substances according to the equation is 1 mol.
4. Proportion:
X mol (H2SO4) – 2 mol (H2O);
– 1 mol – 2 mol from here, X mol (H2SO4) = 1 * 2/2 = 1 mol.
5. Find the mass of acid:
m (H2SO4) = Y * M = 1 * 98 = 98 g.
Answer: you need sulfuric acid weighing 98 g.