How much has the potential energy of a body weighing 1 kg increased if its height has changed from 5 m to 20 m?

Given:

m = 1 kilogram – body weight;

h0 = 5 meters – initial body height;

h1 = 20 meters – final body height;

g = 10 N / kg (Newton per kilogram) is the acceleration of gravity.

It is required to determine dE (Joule) – how much the potential energy of the body will increase with a change in its height.

To determine the change in potential energy, you need to use the following expression:

dE = E1 – E0 = m * g * h1 – m * g * h0 = m * g * (h1 – h0);

dE = 1 * 10 * (20 – 5) = 10 * 15 = 150 Joules.

Answer: the potential energy of the body will increase by 150 Joules.