How much HCI is required to interact with aluminum in an amount of 2 mol?

Reaction equation: 2Al + 6HCl = 2AlCl3 + 3H2
According to the reaction with 2 mol of aluminum, 6 mol of hydrochloric acid reacts, we will make the proportion 2/2 = n (HCl) / 6. Hence the amount of the substance of hydrochloric acid n (HCl) = 6 mol.
Answer: to interact with 2 mol of aluminum, HCl 6 mol is needed.

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