How much heat can be used to heat 0.3 l of water from 12оС-20оС?
| September 14, 2021 | education
V = 0.3 l = 0.3 * 10 ^ -3 m ^ 3.
ρ = 1000 kg / m ^ 3.
t1 = 12 ° C.
t2 = 20 ° C.
C = 4200 J / kg * ° C.
Q -?
The amount of heat Q that is needed to heat water is determined by the formula: Q = C * m * (t2 – t1), where C is the specific heat capacity of water, m is the mass of heated water, t2, t1 are the final and initial water temperatures.
We find the mass of water m by the formula: m = V * ρ, where V is the volume of water, ρ is the density of water.
Q = C * V * ρ * (t2 – t1).
Q = 4200 J / kg * ° C * 0.3 * 10 ^ -3 m ^ 3 * 1000 kg / m ^ 3 * (20 ° C – 12 ° C) = 10080 J.
Answer: to heat water, you need Q = 10080 J of thermal energy
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