How much heat can you heat 300 g of water from 12 to 20 ° C?

The required amount of heat is calculated using the following formula:

Q = С * m * Δt = С * m * (t1 – t0), where according to the condition m (mass of heated water) = 300 g or 0.3 kg, t0 (initial water temperature) = 12 ºС, t1 (water temperature after heating) = 20 ºС; reference data: C (specific heat capacity of water) = 4200 J / (kg * K).

Let’s make a calculation:

Q = 4200 * 0.3 * (20 – 12) = 4200 * 0.3 * 8 = 10080 J or 10.08 kJ.

Answer: To heat 300 g of water at 8 ºС, 10.08 kJ of heat is required.