How much heat does a 300 g aluminum pan receive when heated from 20 ° C to 90 ° C?

Problem data: m (weight of the heated aluminum pan) = 300 g (0.3 kg); t0 (initial temperature of the aluminum pan) = 20 ºС; t (final temperature) = 90 ºС.

Reference values: Ca (specific heat capacity of aluminum) = 920 J / (kg * ºС).

The amount of heat that the aluminum pan will receive is determined by the formula: Q = Ca * m * (t – t0).

Calculation: Q = 920 * 0.3 * (90 – 20) = 19 320 J.

Answer: When heated, an aluminum pan will receive 19 320 Joules of heat.