How much heat does the water in the pond lose when it is cooled by 5 degrees?

How much heat does the water in the pond lose when it is cooled by 5 degrees? The area of the pond is 420 m, the depth is 1.4 m.

Given: Δt (value of water cooling in the pond) = 5 ºС; h (pond depth) = 1.4 m; S (pond surface area) = 420 m2.

Constants: С (specific heat capacity of water) = 4200 J / (kg * ºС); ρ (density of water in the pond) = 1000 kg / m3.

Let’s compose a formula for determining heat losses: Q = C * m * Δt = C * (ρ * V) * Δt = C * (ρ * (S * h)) * Δt.

Let’s calculate: Q = 4200 * (1000 * (420 * 1.4)) * 5 = 12 348 000 000 J ≈ 12.3 kJ.

Answer: Water loses 12.3 kJ of heat.