How much heat is absorbed during the interaction 4.2 gr. nitrogen with oxygen, if TCA N2 + O2 = 2NO – 180kJ

univerkov | August 23, 2021 | education

1. Let’s calculate the chemical amount of nitrogen:

n (N2) = m (N2): M (N2) = 4.2: 28 = 0.15 mol;

2. make up the proportion and find the value of the absorbed heat:

upon interaction of 1 mol of N2, 180 kJ of heat is absorbed;

and when interacting 0.15 mol of N2 – x kJ;

x = 0.15 * 180: 1 = 27 kJ.

Answer: 27 kJ.

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