How much heat is generated in a 100 ohm resistor connected to a 60 V network in 10 minutes?

1. Let’s write down the Joule-Lenz law:
Q = I2 * R * t, where
Q is the amount of heat;
I is the current strength;
R – resistance;
t is time.
2. Since the condition does not contain I, we express it through Ohm’s law:
I = U / R.
3. Replace I in the first formula:
Q = U ^ 2 / R * t.
4. Substitute the values and find the amount of heat:
Q = (60 V) ^ 2/100 Ohm * 600 s = 21600 J = 21.6 kJ.
Answer: 21.6 kJ.