How much heat is needed to bring 400 g of water at a temperature of 20 degrees C to a temperature of 30 degrees?

Task data: m (mass of water) = 400 g (0.4 kg); t0 (initial water temperature) = 20 ºС; t (temperature to which it is necessary to bring the water) = 30 ºС.

Reference values: Sv (specific heat of water) = 4200 J / (kg / K).

The amount of heat for heating 400 g of water is determined by the formula: Q = Sv * m * (t – t0).

Calculation: Q = 4200 * 0.4 * (30 – 20) = 16 800 J (16.8 kJ).

Answer: You need to spend 16.8 kJ of heat.



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