# How much heat is needed to burn 300 grams of alcohol, how much anthracite is needed for this.

June 27, 2021 | education

| The amount of heat released during the complete combustion of alcohol can be calculated using the formula:

Q = q * m, where q is the specific heat of combustion of alcohol (we take q = 2.7 * 10 ^ 7 J / kg), m is the mass of alcohol (m = 300 g = 0.3 kg).

Q = q * m = (2.7 * 10 ^ 7) * 0.3 = 0.81 * 10 ^ 7 J.

Determine the required mass of anthracite:

mа = Q / q, where the specific heat of combustion of anthracite qа = 3 * 10 ^ 7 J / kg.

ma = Q / qa = (0.81 * 10 ^ 7) / (3 * 10 ^ 7) = 0.27 kg = 270 g.

Answer: You need 270 g of anthracite.

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