How much heat is needed to burn 300 grams of alcohol, how much anthracite is needed for this.

The amount of heat released during the complete combustion of alcohol can be calculated using the formula:
Q = q * m, where q is the specific heat of combustion of alcohol (we take q = 2.7 * 10 ^ 7 J / kg), m is the mass of alcohol (m = 300 g = 0.3 kg).
Q = q * m = (2.7 * 10 ^ 7) * 0.3 = 0.81 * 10 ^ 7 J.
Determine the required mass of anthracite:
mа = Q / q, where the specific heat of combustion of anthracite qа = 3 * 10 ^ 7 J / kg.
ma = Q / qa = (0.81 * 10 ^ 7) / (3 * 10 ^ 7) = 0.27 kg = 270 g.
Answer: You need 270 g of anthracite.