How much heat is needed to heat 0.4 kg of water at a temperature of 20 degrees to 30 degrees?
| December 3, 2020 | education
To solve this problem, there is a formula: Q = cmΔt
We paint under our condition: Q = cm (t2-t1)
с – specific heat capacity of the substance (by condition – water)
s = 4200 J / kg * C
Q = 4200 * 0.4 * (30-20) = 16 800 J = 16.8 kJ
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