How much heat is needed to heat 100 g of lead; lead is heated from 50 to its melting point.

Initial data: m (mass of heated lead) = 100 g (0.1 kg); t (temperature that lead had before heating) = 50 ºС.

Reference data: C (specific heat capacity of lead) = 140 J / (kg * K); tmelt (temperature at which lead melting begins) = 327.4 ºС.

The required amount of heat for heating lead is determined by the formula: Q = C * m * (tmelt – t).

Calculation: Q = 140 * 0.1 * (327.4 – 50) = 3883.6 J.

Answer: Heating 100 grams of lead requires 3883.6 Joules of heat.



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