How much heat is needed to heat 20 liters of water in an iron boiler weighing 5 kg from 10 degrees to 50 degrees?

univerkov | December 3, 2020 | education

Given:
V = 20L = 20 kg
m2 = 5 kg
s (water) = 4200
with (iron) = 460
t1 = 10 ° C
t2 = 50 ° C
Find: Q
Decision:
Q = Q1 + Q2
Q1 = c1m1∆t = 4200 * 20 * (50-10) = 3360000 Jack
Q2 = c2m2∆t = 460 * 5 * (50-10) = 92000
Q = 3360000 + 92000 = 3452000

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