How much heat is needed to heat 300g. water from 10 ° C to 60 ° C in an aluminum pot weighing 500 g?

Given: mw (mass of water) = 300 g = 0.3 kg; mk (weight of the aluminum pot) = 500 g = 0.5 kg; t0 (initial temperature of the pot and water) = 10 ºС; t (final temperature) = 60 ºС.

Constants: Ca (heat capacity of aluminum) = 920 J / (kg * ºС); Cw (heat capacity of water) = 4200 J / (kg * ºС).

The required heat for heating water in an aluminum pot: Q = Q1 + Q2 = Cw * mw * (t – t0) + Ca * ma * (t – t0) = (t – t0) * (Cw * mw + Ca * mk) …

Calculation: Q = (60 – 10) * (4200 * 0.3 + 920 * 0.5) = 86 * 10 ^ 3 J (86 kJ).



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