How much heat is needed to heat 32 kg of water from 10 to 65 degrees?

univerkov | August 18, 2021 | education

Given: m (mass of water to be heated) = 32 kg; t0 (initial water temperature) = 10 ºС; t (final temperature) = 65 ºС.

Constants: Sv (specific heat of water) = 4200 J / (kg * K).

The required heat for heating 32 kg of water is calculated by the formula: Q = Cw * m * (t – t0).

Let’s perform the calculation: Q = 4200 * 32 * (65 – 10) = 7 392 000 J ≈ 7.4 MJ.

Answer: To heat 32 kg of water, you need to spend 7.4 MJ of heat.

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