How much heat is needed to heat 350 grams of water from 20 degrees to boiling.
| April 29, 2021 | education
Initial data: m (mass of water) = 350 g (0.35 kg); t0 (initial water temperature) = 20 ºС.
Reference values: tboil (temperature at which water starts boiling, n.o.) = 100 ºС; С (specific heat capacity of water) = 4200 J / (kg * ºС).
The amount of heat for bringing water to a boil is determined by the formula: Q = C * m * (tboil – t0).
Calculation: Q = 4200 * 0.35 * (100 – 20) = 4200 * 0.35 * 80 = 117600 J or 117.6 kJ.
Answer: You need 117.6 kJ of thermal energy.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
