How much heat is needed to heat an aluminum part weighing 300 g from 0 to 100?

univerkov | January 12, 2021 | education

Given: m (mass of the heated aluminum part) = 300 g (in SI m = 0.3 kg); t0 (initial temperature) = 0 ºС; t (final heating temperature of the aluminum part) = 100 ºС.
Constants: Ca (specific heat capacity of aluminum) = 920 J / (kg * ºС).
The required heat for heating the part is calculated by the formula: Q = Ca * m * (t – t0).
Calculation: Q = 920 * 0.3 * (100 – 0) = 27.6 * 10 ^ 3 J or 27.6 kJ.
Answer: To heat an aluminum part, you need to spend 27.6 kJ of heat.

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