How much heat is needed to heat one ton of lead by 5 degrees?

To determine the cost of heat for heating the taken ton of lead, we will use the formula: Q = Cc * m * Δt.

Variables and constants: Cc – specific heat capacity of lead (Cc = 140 J / (kg * K)); m is the mass of the lead being heated (m = 1 t = 1 * 10 ^ 3 kg); Δt – temperature change (Δt = 5 ºС).

Calculation: Q = Cc * m * Δt = 140 * 1 * 10 ^ 3 * 5 = 700 * 10 ^ 3 J (700 kJ).

Answer: To heat a ton of lead, you need to spend 700 kJ of heat.



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