How much heat is needed to heat water in a pool 100 m long, 6 m wide and 2 m deep

How much heat is needed to heat water in a pool 100 m long, 6 m wide and 2 m deep at a temperature of 16 ° C to a temperature of 25 ° C?

Data: l (pool length) = 100 m; s (pool width) = 6 m; h (pool depth) = 2 m; t1 (water temperature in the pool before heating) = 16 ºС; t2 (final water temperature) = 25 ºС.

Reference values: according to the condition Sv (heat capacity of water) = 4200 J / (kg * ºС); ρw (water density) = 1000 kg / m3.

Let’s compose the formula: Q = C * m * Δt = C * ρw * V * (t2 – t1) = C * ρw * l * s * h * (t2 – t1).

Calculation: Q = 4200 * 1000 * 100 * 6 * 2 * (25 – 16) = 45 360 000 000 J = 45 360 MJ.

Answer: 45360 MJ of heat.