How much heat is needed to make 300 gr. melt ice, and heat the resulting water to a temperature of 70 C?
| December 14, 2020 | education
Q = cmT, but we need a formula (designed to melt a substance / material): Q = lambda * m + c * m * T.
Q = lambda * m + c * m * dT = 3.3 10 ^ 5 J / kg * 0.3 kg + 4200 J / kg * 0.3 kg * 70 = 99000 + 88200 = 187200 J = 187.2 kJ.
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