How much heat is needed to melt 300 g of lead at the melting point?
| February 11, 2021 | education
Initial data: m (mass of taken lead) = 300 g (0.3 kg); taken lead is at its melting temperature.
Reference data: according to the condition λ (specific heat of fusion of lead) = 24 kJ / kg (24 * 10 ^ 3 J / kg).
The required amount of heat for melting 300 g of lead is determined by the formula: Q = λ * m.
Calculation: Q = 24 * 10 ^ 3 * 0.3 = 7.2 * 10 ^ 3 J or 7.2 kJ.
Answer: You need 7.2 kJ of heat.
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