How much heat is needed to melt a 2x5x10 cm lead plate taken at the melting point?

How much heat is needed to melt a 2x5x10 cm lead plate taken at the melting point? The density of lead is 11.3 * 10 ^ 3 kg / m3, the specific heat of fusion of lead is 2.5 * 10 ^ 4 J / kg ..

Initial data: dimensions of the lead plate 2 x 5 x 10 cm (0.02 x 0.05 * 0.1 m); the plate is taken at the melting point.
Reference values: according to the condition ρс (lead density) = 11.3 * 10 ^ 3 kg / m3; λ (specific heat of fusion of lead) = 2.5 * 10 ^ 4 J / kg.
The amount of heat for melting a lead plate is calculated by the formula: Q = λ * m = λ * ρс * V = λ * ρс * a * b * c.
Calculation: Q = 2.5 * 104 * 11.3 * 10 ^ 3 * 0.02 * 0.05 * 0.1 = 28 250 J (28.25 kJ).
Answer: You need 28.25 kJ of heat.