How much heat is needed to melt a 3kg lead ingot heated to a temperature of 327?
| January 29, 2021 | education
Given:
m = 3 kilograms is the mass of lead;
T = 327 degrees Celsius – lead temperature;
q = 22600 J / kg is the specific heat of lead.
It is required to find the amount of heat Q (Joule) required to melt lead of mass m.
Since lead is already heated to its melting point, then:
Q = q * m = 22600 * 3 = 67800 Joules = 67.8 kJ.
Answer: to melt lead, you need an amount of heat equal to 67.8 kJ.
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