How much heat is needed to obtain steam of 100 ℃ from 2 kg ice taken at a temperature of -10 ℃?

univerkov | August 31, 2021 | education

Q = Q1 + Q2 + Q3 + Q4.
Q = С1 * m * (tк1 – tн1), С1 = 2100 J / (kg * К)), m = 2 kg, tк = 0 ºС, tн = -10 ºС.
Q2 = λ * m, λ = 34 * 10 ^ 4 J / kg.
Q3 = C2 * m * (tк2 – tн2), С2 = 4200 J / (K * kg)), tк2 = 100 ºС, tн2 = 0 ºС.
Q4 = L * m, L = 2.3 * 10 ^ 6 J / kg.
Q = C1 * m * (tk1 – tn1) + λ * m + C2 * m * (tk2 – tn2) + L * m = 2100 * 2 * (0 – (-10)) + (34 * 10 ^ 4) * 2 + 4200 * 2 * (100 – 0) + 2.3 * 10 ^ 6 * 2 = 6162000 J = 6.162 MJ.
Answer: It is necessary to spend 6,162 MJ of heat.

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