How much heat is needed to transform 500 g of ice taken at a temperature of 0 ° C into water

How much heat is needed to transform 500 g of ice taken at a temperature of 0 ° C into water at a temperature of 40 ° C?

Data: m (mass of taken ice (water)) = 500 g (0.5 kg); t0 (ice temperature before heating) = 0 ºС (is the ice melting temperature); t (temperature of water obtained from ice) = 40 ºС.

Reference values: λ (specific heat of melting of ice) = 3.4 * 105 J / kg; C (specific heat of water) = 4200 J / (kg * ºС).

The formula for calculating the required amount of heat: Q = Q1 + Q2 = λ * m + C * m * (t – t0) = (λ + C * (t – t0)) * m.

Q = (3.4 * 105 + 4200 * (40 – 0)) * 0.5 = 254,000 J (254 kJ).