How much heat is released during the complete combustion of kerosene with a volume of 2 liters
| September 10, 2021 | education
How much heat is released during the complete combustion of kerosene with a volume of 2 liters and a density of 800 kg / m3?
These tasks: V (volume of kerosene taken) = 2 liters (in SI V = 2 * 10 ^ -3 m3).
Constants: qк (heat of combustion of kerosene) = 4.6 * 10 ^ 7 J / kg; by condition ρ (density) = 800 kg / m3.
The heat that should have been released during the combustion of 2 liters of kerosene can be determined by the formula: Q = qк * m = qк * ρ * V.
Calculation: Q = 4.6 * 10 ^ 7 * 800 * 2 * 10 ^ -3 = 73.6 * 10 ^ 6 J = 73.6 MJ.
Answer: When 2 liters of kerosene are burned, 73.6 MJ of heat should be released.
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