How much heat is released during the crystallization of 1 kg of lead taken at a temperature of 327 degrees?
| April 25, 2021 | education
Given:
m = 1 kilogram is the mass of lead;
T = 327 degrees Celsius – the temperature at which lead is located;
q = 25 kJ / kg = 25000 Joule / kilogram is the specific heat of fusion of lead.
It is required to determine Q (Joule) – how much heat will be released during crystallization of lead with mass m.
The crystallization temperature of lead (like the melting point) is 327 degrees Celsius. This means that the lead is already at the crystallization temperature and no additional cooling is required. Then:
Q = q * m = 25000 * 1 = 25000 Joules = 25 kJ.
Answer: during crystallization of 1 kilogram of lead, an energy equal to 25 kJ will be released.
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