How much heat is released in 10 minutes by a tungsten conductor 90 cm

How much heat is released in 10 minutes by a tungsten conductor 90 cm long and a cross-sectional area of 0.04 mm2 at a circuit current of 1.2 A.

To find the heat released on a tungsten conductor, we will use the Joule-Lenz law: Q = I ^ 2 * R * t = I ^ 2 * (ρ * l / S) * t.

Constants and variables: I – current in the circuit (I = 1.2 A); ρ – electrical resistivity of tungsten (ρ = 0.055 Ohm * mm2 / m); l is the length of the tungsten conductor (l = 90 cm = 0.9 m); S – cross-sectional area (S = 0.04 mm2); t – time (t = 10 min = 600 s).

Calculation: Q = 1.2 ^ 2 * (0.055 * 0.9 / 0.04) * 600 = 1069.2 J.

Answer: The conductor will give off 1069.2 J of heat.